-3pq - 3qr-2 nbsp- 18 pq-2r - nbsp-9pq-2-9qr-2-18p9p-2q-9pr-2-9pq9p-2q-2-9q-2r-29p-2q-2-9qr-2-9p

The correct option is C 9p^2q^2+9q^2r^2Given: (3pq + 3qr)^2 nbsp; 18 pq^2r Consider nbsp;(3pq + 3qr)^2 Expand this using the identity ((a + b)^2 nbsp;= ...

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Byju's Answer

Standard VIII

Mathematics

Factorisation Using Algebraic Identities

(3pq + 3qr)^2...

Question

${(3 p q + 3 q r)}^{2} - 18 p q^{2} r$ = .

9 p q^{2} + 9 q r^{2} - 18 p

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9 p^{2} q + 9 p r^{2} - 9 p q

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9 p^{2} q^{2} + 9 q^{2} r^{2}

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9 p^{2} q^{2} + 9 q r^{2} + 9 p

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Solution

The correct option is C $9 p^{2} q^{2} + 9 q^{2} r^{2}$
Given: ${(3 p q + 3 q r)}^{2} - 18 p q^{2} r$

Consider ${(3 p q + 3 q r)}^{2}$
Expand this using the identity
$({(a + b)}^{2} = a^{2} + 2 a b + b^{2})$
${(3 p q + 3 q r)}^{2} = 9 {(p)}^{2} {(q)}^{2} + 9 {(q)}^{2} {(r)}^{2} + 18 p q^{2} r$

${(3 p q + 3 q r)}^{2} - 18 p q^{2} r = 9 p^{2} q^{2} + 9 q^{2} r^{2} + 18 p q^{2} r - 18 p q^{2} r$
$= 9 p^{2} q^{2} + 9 q^{2} r^{2}$

Suggest Corrections

(3pq+3qr)2−18pq2r = .

The correct option is C 9p2q2+9q2r2Given: (3pq+3qr)2−18pq2r Consider (3pq+3qr)2 Expand this using the identity ((a+b)2=a2+2ab+b2) (3pq+3qr)2=9(p)2(q)2+9(q)2(r)2+18pq2r (3pq+3qr)2−18pq2r=9p2q2+9q2r2+18pq2r−18pq2r =9p2q2+9q2r2

${(3 p q + 3 q r)}^{2} - 18 p q^{2} r$ = .