-3 x-1-2For what possible values of x- is the above equation satisfied- A- 3-2 and -1B- -3-2 and 1C- 1-2 and -1D- -1-3 and 1

The correct option is D 1/3 and 1|3x 1|=2 (3x 1)=± 2 (3x 1)=2 (3x 1)= 2 3x=3 3x= 1 x=1 ...

You visited us 1 times! Enjoying our articles? Unlock Full Access!

Byju's Answer

Standard XII

Mathematics

Manipulating absolute value equations

|3 x-1|=2For ...

Question

$| 3 x - 1 | = 2$
For what possible values of x, is the above equation satisfied?

\frac{3}{2}

and

- 1

No worries! We‘ve got your back. Try BYJU‘S free classes today!

- \frac{3}{2}

and

1

No worries! We‘ve got your back. Try BYJU‘S free classes today!

\frac{1}{3}

and

- 1

No worries! We‘ve got your back. Try BYJU‘S free classes today!

- \frac{1}{3}

and

1

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

Open in App

Solution

The correct option is D $- \frac{1}{3}$ and $1$
$| 3 x - 1 | = 2$
$(3 x - 1) = \pm 2$
$(3 x - 1) = 2$ $(3 x - 1) = - 2$
$3 x = 3$ $3 x = - 1$
$x = 1$ $x = - \frac{1}{3}$

Suggest Corrections

Similar questions

In the above cross, what is the ratio between homozygous plants and heterozygous plants of $F_{2}$ progeny?

Equation of the line passing through (1, 2) and parallel to the line

$y = 3 x - 1$ is

If $\frac{\sqrt{3} - 1}{\sqrt{3} + 1} = a + b \sqrt{3}$ , then the values of $^{'} a^{'}$ and $^{'} b^{'}$ are _________.

If the equation $a_{1}$ + $a_{2} c o s 2 x$ + $a_{3} s i n^{2} x$ = 1 is satisfied by every real values of x, then the number of possible values of the triplet $(a_{1}, a_{2}, a_{3})$

Q. If

α

and

β

are the roots of the quadratic equation

(x - 2) (x - 3) + (x - 3) (x + 1) + (x + 1) (x - 2) = 0

, then the value of

\frac{1}{(α + 1) (β + 1)} + \frac{1}{(α - 2) (β - 2)} + \frac{1}{(α - 3) (β - 3)}

Join BYJU'S Learning Program

|3x−1|=2 For what possible values of x, is the above equation satisfied?

The correct option is D −13 and 1|3x−1|=2 (3x−1)=±2 (3x−1)=2 (3x−1)=−2 3x=3 3x=−1 x=1 x=−13

$| 3 x - 1 | = 2$
For what possible values of x, is the above equation satisfied?

The correct option is D $- \frac{1}{3}$ and $1$
$| 3 x - 1 | = 2$
$(3 x - 1) = \pm 2$
$(3 x - 1) = 2$ $(3 x - 1) = - 2$
$3 x = 3$ $3 x = - 1$
$x = 1$ $x = - \frac{1}{3}$