Question

$3x^2-243=0$

Answer 1

$$\begin{gathered} \text{Given:} \\ \text{3}{x}^2-243=0 \\ \Rightarrow 3(x^2-81)=0 \\ \Rightarrow {\left(x\right)}^2-{\left(9\right)}^2=0 \\ \Rightarrow (x+9)(x-9)=0 \\ \Rightarrow x+9=0\text{or}x-9=0 \\ \Rightarrow x=-9\text{or}x=9 \\ \text{Hence,}-\text{9 and 9 are the roots of the equation 3}{x}^2-243=0. \end{gathered}$$