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Question

4.00 moles of N2 and 3.00 moles of H2 are allowed to react in the presence of iron as a catalyst according to the reaction:
N2(g)+3H2(g)Fe2NH3(g). The number of molecules of the gas left unreacted will be

A
1.86×1023
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B
6.02×1023
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C
18×1023
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D
1.20×1023
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Solution

The correct option is C 18×1023
N2+3H22NH3
According to the balanced equation, one mole of N2 reacts with 3 moles of H2
So, 4 moles of N2 will require 12 moles of H2 but only 3 moles of H2 is given. Hence H2 is the limiting reagent.
moles of N2 left =41=3
Number of molecules of N2 left =3×6×1023=18×1023

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