The number of molecules in 89-6 L of a gas at STP are A- 6-022 - 1023B- 2 - 6-022 - 1023C- 3 - 6-022 - 1023D- 4 - 6-022 - 1023

The correct option is D 22.4 L of a gas at STP = 6.022 × 10^23 molecules 89.6L of a gas at STP= (6.022 × 10^23× 89.6)/22.4 = 4 × 6.022 × 10^23 molecules ...

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Standard X

Chemistry

Mole Concept

The number of...

Question

The number of molecules in 89.6 L of a gas at STP are

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Solution

The correct option is D
22.4 L of a gas at STP = $6.022 \times 10^{23}$ molecules
89.6L of a gas at STP= $\frac{(6.022 \times 10^{23} \times 89.6)}{22.4} = 4 \times 6.022 \times 10^{23}$ molecules

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The number of molecules in 89.6 L of a gas at STP are

The correct option is D 22.4 L of a gas at STP = 6.022×1023 molecules 89.6L of a gas at STP= (6.022×1023×89.6)22.4=4×6.022×1023 molecules

The correct option is D
22.4 L of a gas at STP = $6.022 \times 10^{23}$ molecules
89.6L of a gas at STP= $\frac{(6.022 \times 10^{23} \times 89.6)}{22.4} = 4 \times 6.022 \times 10^{23}$ molecules