Question

$4g{H}_2,32g{O}_2,14g{N}_2$ and $11gC{O}_2$ are taken in a bulb of $500ml$. Which one of the these has maximum active mass?

• A. $H_2$
• B. $O_2$
• C. $N_2$
• D. $C{O}_2$

Answer 1

Answer: (A)

$H_2$

As we know that,

$\text{Active mass}=\frac{\text{Given mass}}{\text{Molecular mass}\times {\text{Volume}}_{\left(\text{in L}\right)}}$

Given mass of $H_2=4g$

Given mass of $O_2=32g$

Given mass of $N_2=14g$

Given mass of $C{O}_2=11g$

Molecular mass of $H_2=2g$

Molecular mass of $O_2=32g$

Molecular mass of $N_2=28g$

Molecular mass of $C{O}_2=44g$

Volume $=500mL=\frac{500}{1000}=0.5L$

$\therefore$ Active mass for $H_2=\frac{4}{2\times 0.5}=4mol/L$

Active mass for $O_2=\frac{32}{32\times 0.5}=2mol/L$

Active mass for $N_2=\frac{14}{28\times 0.5}=1mol/L$

Active mass for $C{O}_2=\frac{11}{44\times 0.5}=0.5mol/L$

Hence, 4g $H_2$ have maximum active mass.