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Stoichiometric Calculations

4 gH 2, 32 g ...

Question

$4 g H_{2}, 32 g O_{2}, 14 g N_{2}$ and $11 g C O_{2}$ are taken in a bulb of 500 ml. which one of these has maximum active mass?

$H_{2}$

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$O_{2}$

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$N_{2}$

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$C O_{2}$

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Solution

The correct option is A
$H_{2}$

Active mass = concentraiton

Active mass of $H_{2} = \frac{\frac{4}{2}}{\frac{500}{1000}} = 4$

Active mass of $O_{2} = \frac{\frac{32}{32}}{\frac{500}{1000}} = 2$

Active mass of $N_{2} = \frac{\frac{14}{28}}{\frac{500}{1000}} = 1$

Active mass of $C O_{2} = \frac{\frac{11}{44}}{\frac{500}{1000}} = 0.5$

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Similar questions

4 g H_{2}, 32 g O_{2}, 14 g N_{2}

11 g C O_{2}

500 m l

4 g

H_{2}

32 g

O_{2}

14 g

N_{2}

11 g

{C O}_{2}

500 m l

4

H_{2}

32

O_{2}

14

N_{2}

11

{C O}_{2}

500

Which of hte following contains maximum number of molecules:
(a) 4 g of $O_{2}$ (b) 4 g of $N H_{3}$
(c) 4 g of $C O_{2}$ (d) 4 g of $S O_{2}$

X m l

H_{2}

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