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Question

# 4g NaOH is added in 100mL of 0.5M NaOH solution and solution was made 1L with addition of water 20mL of above solution can:

A
Completely neutralise 20mL of 0.4M H2C2O4 (oxalic acid)
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B
Completely neutralise 20mL of 0.5M HNO3 solution
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C
Completely neutralise 15mL of 0.2M HCl solution
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D
None of these
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Solution

## The correct option is C Completely neutralise 15mL of 0.2M HCl solutionMolarity= Number of moles of soluteVolume0.5M NaOH is 0.5 moles of NaOH dissolved in 1L of solvent100ml of 0.5M NaOH=100×0.5=50mmol NaOHMass of NaOH=50×10−3×40=2g4g NaOH is added to 100ml of 0.5M NaOH∴6g of NaOH is presentMolarity= 6/40100/1000=1.5MM1V1=M2V2∴M2=1.5×1001000=0.15M (After dilution)∴(MV)NaOH=0.15×20=3=15×0.2=(MV)HCl∴ It completely neutralises 15ml of 0.2M HCl solution.

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