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Question

4g of an ideal gas was introduced into a bulb of volume of \0.821 dm3 at certain pressure, P and temperature The above bulb was placed in a thermostat mentioned at temperature (T+125) K of 0.8 g of the gas was left off to keep the original pressure. Calculate the pressure in atmospheres.[Molecular weight of the gas is 40 gmoleI and R value is 0.0821 litatm klmol.

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Solution

As given,
Initial no.of moles=440=0.1
Final no.of moles =3.240=0.08
Since P and V are constant,
n1T1=n2T2
0.1T1=0.08(T1+125)
T1=500K
From PV=nRT
P=0.1×0.082×5000.821=5atm.

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