The correct option is A 8
Let one man's 1 day's work =x
and one woman's 1 day's work =y.
Then, 4x+10y=13×14=112
⇒2x+5y=124 ⋯(i)
And, 6x+12y=29×12=19
⇒2x+4y=127 ⋯(ii)
Subtracting (ii) from (i), we get
y=124−127=1216
Now, (6 men + 12 women)'s 3 day's work =(19×3)=13
Work completed =(13+29+13)=89
∴ Remaining work =(1−89)=19
One women's 3 day's work
=(1216×3)=172
In 3 days, 172 work is done by one woman.
∴ In 3 days, 19 work is done by =(19×72)=8 woman.