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Standard XII

Chemistry

Arrhenius Acid

4 moles of A ...

Question

4 moles of A are mixed with 4 moles of B, then 2 moles of C are formed at equilibrium, according to the reaction,
A + B $⇌$ C + D.
The equilibrium constant is :

4

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1

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\sqrt{2}

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\sqrt{4}

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Solution

The correct option is B $1$
$A + B ⇌ C + D 4400 4 - 24 - 222 2222 K_{c} = \frac{2 \times 2}{2 \times 2} = 1$

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Similar questions

4 moles of A are mixed with 4 moles of B, then 2 moles of C are formed at equilibrium, according to the reaction,
A + B $⇌$ C + D.
The equilibrium constant is :

4

moles of

A

are mixed with

4

moles of

B

when

2

moles of

C

are formed at equilibrium according to the reaction

A + B ⇌ C + D

The value of the equilibrium constant is :

According to the reaction,

4

mole of

A

are mixed with

4

mole of

B

when

2

mole of

C

are formed at equilibrium.

A + B ⇌ C + D

Find the equilibrium constant.

4 moles of A are mixed with 4 moles of B. At equilibrium for the reaction

A + B $⇌$ C + D, 2 moles of C and D are formed. The equilibrium constant for the

reaction will be

4 m o l e s

of A are mixed with

4 m o l e s

of B when

2 m o l e s

of C are formed at equilibrium. According to the equation

A + B ⇋ C + D

. Find the equilibrium constant:

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4 moles of A are mixed with 4 moles of B, then 2 moles of C are formed at equilibrium, according to the reaction, A + B ⇌ C + D. The equilibrium constant is :

The correct option is B 1A + B ⇌ C + D4 4 0 04−2 4−2 2 22 2 2 2Kc=2×22×2=1

4 moles of A are mixed with 4 moles of B, then 2 moles of C are formed at equilibrium, according to the reaction,
A + B $⇌$ C + D.
The equilibrium constant is :

The correct option is B $1$
$A + B ⇌ C + D 4400 4 - 24 - 222 2222 K_{c} = \frac{2 \times 2}{2 \times 2} = 1$