Question

$4\mu F$ and $6\mu F$ capacitors are joined in series and $500v$ are applied between the outer plates of the system. What is the charge on each plate ?

• A. $1\cdot 2\times {10}^{3}C$
• B. $6\cdot 0\times {10}^{3}C$
• C. $5\cdot 0\times {10}^{-3}C$
• D. $2\cdot 0\times {10}^{-3}C$

Answer 1

The correct option is A $1\cdot 2\times {10}^{3}C$

Since the capacities are connected in series

$\frac{1}{C_{eq}}=\frac{1}{C_1}+\frac{1}{C_2}$

$\frac{1}{C_{eq}}=\frac{1}{4\mu }+\frac{1}{6\mu }$

$C_{eq}=\frac{12\mu }{5}$

$C=\frac{Q}{V}$

$\frac{12\mu }{5}=\frac{Q}{500}$

$Q=1.2\times {10}^3$