Question

Question 128

4 squares each of the side 10 cm have been cut from each corner of a rectangular sheet of paper of size 100 cm $\times$ 80 cm. From the remaining piece of paper, an isosceles right triangle is removed whose equal sides are each of 10 cm length. Find the area of the remaining part of the paper.

Answer 1

Area of each square = $(10{)}^{2}c{m}^2=100c{m}^2$ [$\because$ area of square = (side)^2]

Area of rectangular sheet =$100\times 80c{m}^2$ [$\because$ area of rectangle = length $\times$ breadth ]

= 8000 $c{m}^2$

Area of an isosceles right triangle $=\frac{1}{2}\times 10\times 10=50c{m}^2$ [$\because$ area of an isosceles right triangle = $\frac{1}{2}\times base\times height$]

$\therefore$ Area of remaining part of paper = 8000 - 4 $\times$ 100 - 50

= 7550 $c{m}^2$