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Question

4 g of an ideal gas was introduced into a bulb of volume of 0.821 dm3 at certain pressure, P and temperature T. The above bulb was placed in a thermostat mentioned at temperature (T+125)K of 0.8 gm of the gas was left off to keep the original pressure. Calculate the pressure in atmosphere. [Molecular weight of the gas is 40 g mole1 and R value is 0.0821 lit-atm-k1mol]

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Solution


Initial no.of moles (n)=440=0.1
Final no.of moles (n)=3.240=0.08
Since P and V are constant
n1T1=n2T2
0.1T1=0.08(T1+125)
T1=500K
From ,
PV=nRT
P=0.1×0.0821×5000.821=5 atm

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