Question

$4\text{g}$ of copper was dissolved in concentrated nitric acid. The copper nitrate on strong heating gave $5\text{g}$ of its oxide. The equivalent weight of copper is _______.

• A. $12\text{g}$
• B. $16\text{g}$
• C. $32\text{g}$
• D. $34\text{g}$

Answer 1

The correct option is C $32\text{g}$

Let the equivalent weight of copper be $M$
Weight of the metal oxide = $5\text{g}$; weight of the metal = $4\text{g}$
Weight of oxygen = $1\text{g}$

$\frac{\text{weight of the metal}}{\text{weight of oxygen}}=\frac{\text{equivalent weight of the metal}}{\text{equivalent weight of oxygen}}$

$\Rightarrow \frac{4}{1}=\frac{M}{8}$
So, the equivalent weight of copper = $32\text{g}$