$4 mol$ of a mixture containing one mol each of $L i N O_{3}, N a N O_{3}, C a (N O_{3})_{2}$ and $M g (N O_{3})_{2}$ is decomposed by strongly heating the total number of moles of $N O_{2}$ evolved is (assuming complete decomposition of all the salts.)

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Solution

$2 L i N O_{3} Δ ⟶ L i_{2} O + 2 N O_{2} + \frac{1}{2} O_{2}$
1 mol of $L i N O_{3}$ will produce $N O_{2} = 1$
$2 M g (N O_{3})_{2} Δ ⟶ 2 M g O + 4 N O_{2} + O_{2}$
1 mol of Mg $(N O_{3})_{2}$ will produce $N O_{2} = 2$
$2 C a (N O_{3})_{2} Δ ⟶ 2 C a O + 4 N O_{2} + O_{2}$
1 mol of $C a (N O_{3})_{2}$ will produce $N O_{2} = 2$
$2 N a N O_{3} Δ ⟶ 2 N a N O_{2} + O_{2}$
$∴$ Total number of moles of $N O_{2}$ produced = 5

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L i N O_{3}, M g N O_{3} N a N O 3, C a (N O_{3})_{2}

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4 mol of a mixture containing one mol each of LiNO3, NaNO3, Ca(NO3)2 and Mg(NO3)2 is decomposed by strongly heating the total number of moles of NO2 evolved is (assuming complete decomposition of all the salts.)

2LiNO3Δ⟶Li2O+2NO2+12O2 1 mol of LiNO3 will produce NO2=1 2Mg(NO3)2Δ⟶2MgO+4NO2+O2 1 mol of Mg (NO3)2 will produce NO2=2 2Ca(NO3)2Δ⟶2CaO+4NO2+O2 1 mol of Ca(NO3)2 will produce NO2=2 2NaNO3Δ⟶2NaNO2+O2 ∴ Total number of moles of NO2 produced = 5

$4 mol$ of a mixture containing one mol each of $L i N O_{3}, N a N O_{3}, C a (N O_{3})_{2}$ and $M g (N O_{3})_{2}$ is decomposed by strongly heating the total number of moles of $N O_{2}$ evolved is (assuming complete decomposition of all the salts.)