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Osmotic Pressure and Osmotic Potential

40. 18 L mixt...

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40. 18 L mixture of N2 and H2 gives a maximum 6L of NH3 at same temperature and pressure then what will be ratio of N2 and H2 initially taken

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Q. If a mixture of

3

H_{2}

and one mole of

N_{2}

is completely converted into

N H_{3}

. What would be the ratio of the initial and final volume at same temperature and pressure?

40

of a mixture of

0.2 m o l e

N_{2}

0.6 m o l e

H_{2}

N H_{3}

according to the equation,

N_{2} (g) + 3 H_{2} (g) ⇌ 2 N H_{3} (g)

at constant temperature and pressure. Then the ratio of the final volume to the initial volume of gases are :

40

0.2 m o l e

N_{2}

0.6 m o l e

H_{2}

{N H}_{3}

according to the equation

N_{2} (g) + 3 H_{2} (g) ⇌ 2 {N H}_{3} (g)

, at constant temperature and pressure. Then the ratio of the final volume to the initial volume of gases is:

Q. 40% of a mixture of 0.2 mole of

N_{2}

and 0.6 mole of

H_{2}

N H_{3}

according to the equation,

N_{2} (g) + 3 H_{2} (g) ⇌ 2 N H_{3} (g)

at constant temperature and pressure. Then the ratio of the final volume to the initial volume of gases are :

40 %

of a mixture of

0.2

N_{2}

0.6

H_{2}

N H_{3}

according to the equation,

N_{2} (g) + 3 H_{2} (g) ⇌ 2 N H_{3} (g)

at constant temperature and pressure.
Then the ratio of the final volumn to the initial volumn of gases is as-

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Osmotic Pressure and Osmotic Potential

Standard XII Biology