40.5 g + 62.4 g = ?
1029 kg
0.1029 kg
0.1029 g
10.29 g
40.5 g + 62.4 g = 102.9 g
1 kg = 1000 g
1 g = 1 ÷ 1000 kg
102.9 g = 0.1029 kg
Calculate the number of electrons required to deposit 40.5g of Al.