Question

$40$g MgO dissolves in $H_{2}O$ to form $200$ ml of solution, if density of solution is $1.5$g/ml. Calculate ppm of solute.

Answer 1

MgO is solute & $H_{2}O$ is solvent

weight of solute $=40g$ volume of solution = 200 ml

ppm by weight to volume $=\frac{amountofsolute\left(mg\right)}{amountofsolution\left(L\right)}$

$\therefore ppm=\frac{40\times {10}^{+3}}{200\times {10}^3}$ ${}_L^{mg}=0.2mg/L$