Question

40 litres of milk was mixed with 50 litres of water in jar A. Some parts of this mixture is then removed and poured into jar B containing 13 litres of pure milk in it. If the ratio of milk and water in Jar B is 5: 3, then what is the amount of mixture remaining in jar A?

• A. 27 L
• B. 63 L
• C. 45 L
• D. 39 L

Answer 1

The correct option is B 63 L

Quantity of solution in Jar A = 90 L
Milk: water ratio in jar B will be $=13+\left(\frac{4}{9}\right)x:\left(\frac{5}{9}\right)x\text{Now,}3(13+\frac{4}{9}x)=5\left(\frac{5}{9}x\right)$
Solving, we get x=27 litres
Quantity of mixture remaining in Jar A = 90- 27 = 63 L