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Standard XII

Chemistry

Stoichiometric Calculations

40 ml of CO w...

Question

$40$ ml of CO was mixed with $100$ ml of $O_{2}$ and the mixture was exploded. On cooling, the reaction mixture was shaken with KOH. What volume of gas is left?

60 ml of

O_{2}

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80 ml of

O_{2}

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20 ml of

C O

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40 ml of

C O_{2}

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Solution

The correct option is B 80 ml of $O_{2}$
Reaction:
$C O + \frac{1}{2} O_{2} ⟶ C O_{2}$
$40 m l$ $20 m l$ $40 m l ↓$

$K O H$ absorbed $40$ ml of $C O_{2}$ .

So, volume of $O_{2} = (100 - 20) = 80 m l$

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40 ml of CO was mixed with 100 ml of O2 and the mixture was exploded. On cooling, the reaction mixture was shaken with KOH. What volume of gas is left?

The correct option is B 80 ml of O2Reaction:CO+12O2⟶CO240ml 20ml 40ml↓KOH absorbed 40 ml of CO2. So, volume of O2=(100−20)=80 ml

$40$ ml of CO was mixed with $100$ ml of $O_{2}$ and the mixture was exploded. On cooling, the reaction mixture was shaken with KOH. What volume of gas is left?

The correct option is B 80 ml of $O_{2}$
Reaction:
$C O + \frac{1}{2} O_{2} ⟶ C O_{2}$
$40 m l$ $20 m l$ $40 m l ↓$

$K O H$ absorbed $40$ ml of $C O_{2}$ .

So, volume of $O_{2} = (100 - 20) = 80 m l$