40 waves pass through a point in 0.5s at 0oC. The distance between one compression and adjacent rarefaction is 8m. Find the velocity of the sound wave at 2457K.
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Solution
If 40waves pass through a point in 0.5s then it means one wave takes 0.540sec
This means that the time period 'T' is 0.540sec
The distance between one compression and adjacent rarefaction is half of wavelength. So wavelength λ=16m
We know that speed=λT
Thus the speed at 00Celcius=v1=16÷0.540=16×400.5=1280m/s
From the given conditions we have T1=00Celcius=2730Kelvin and T2=2457K
We know that v2v1=√T2T1=√2457273=3
Hence v2=v1×3=1280×3=3840 m/s
The velocity of the sound wave at 2457K is 3840m/s