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Question

400 mL of a strong acid solution of pH = 3 is mixed with 600 mL of another strong base solution of pOH = 4. The pH of resulting solution will be :
[Given, log(3.4)=0.531]

A
3.08
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B
4.0
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C
4.2
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D
3.46
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Solution

The correct option is D 3.46

pHsolution1=3 ; C1=[H+]=103pOHsolution2=4 ; C2=[OH]=104Cf=[H+]remains after neutralization V1=400 mL , V2=600 mLVf=V1+V2=1000 mLApplying:
C1V1C2V2=CfVfCf=C1V1C2V2Vf=(103× 400)(104× 600)1000 =3.4×104pH= log10[3.4×104]pH=3.46

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