Question

40ml of a gas is collected at ${25}^{o}C$ pressure remaining constant, if the temperature is raised to ${50}^{o}C$, the final volume of the gas in ml is:

• A. $\frac{40\times 323}{298}$
• B. $\frac{40\times 25}{50}$
• C. $\frac{40\times 298}{323}$
• D. $\frac{40\times 50}{25}$

Answer 1

The correct option is A $\frac{40\times 323}{298}$

According to Charles's Law :-

$V\propto T\frac{V_1}{T_1}=\frac{V_2}{T_2}{V}_1=40ml{V}_2=?T_1=25℃=25+273=298K{T}_2=50℃=50+273=323K⟹\frac{40}{298}=\frac{V_2}{323}\therefore V_2=\frac{40\times 323}{298}litres$