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Electric Field inside a Conductor under Electrodynamic Conditions

41. Two charg...

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41. Two charges of +25 × 10–9 coulomb and –25 × 10–9 coulomb are placed 6 m apart. Find the electric field intensity ratio at points 4 m from the centre of the electric dipole (i) on axial line (ii) on equatorial line (1) 1000 49 (2) 49 1000 (3) 500 49 (4) 49 500

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Q. Two charges of

+ 25

10^{- 9}

- 25

10^{- 9}

coulomb are placed

6

m apart. Find the electric field intensity ratio at points

4

m from the centre of the electric dipole
(i) on axial line
(ii) on equatorial line

+ 25 \times 10^{- 9}

- 25 \times 10^{- 9}

C are placed 6 m apart. Find the electric field intensity ratio at point 4 m from the centre of the electric dipole

(i) on axial line

(ii) on equatorial line

+ 3.2 \times 10^{- 19}

- 3.2 \times 10^{- 19}

2.4 ˙ A

apart form an electric dipole. It is placed in a uniform electric field of intensity

4 \times 10^{5}

volt/m. The electric dipole moment is

Q. Two opposite charges each of magnitude

2 μ C

1 c m

apart. Find a electric field at a distance of

5 c m

from the mid-point on axial line of the dipole. Also find the field on equatorial line at the same distance from mid-point.

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