CameraIcon

SearchIcon

MyQuestionIcon

1

You visited us 1 times! Enjoying our articles? Unlock Full Access!

Electric Field inside a Conductor under Electrodynamic Conditions

41. Two charg...

Question

41. Two charges of +25 × 10–9 coulomb and –25 × 10–9 coulomb are placed 6 m apart. Find the electric field intensity ratio at points 4 m from the centre of the electric dipole (i) on axial line (ii) on equatorial line (1) 1000 49 (2) 49 1000 (3) 500 49 (4) 49 500

Open in App

Solution

Suggest Corrections

thumbs-up

56

Similar questions

Q. Two charges of

+ 25

10^{- 9}

- 25

10^{- 9}

coulomb are placed

6

m apart. Find the electric field intensity ratio at points

4

m from the centre of the electric dipole
(i) on axial line
(ii) on equatorial line

+ 25 \times 10^{- 9}

- 25 \times 10^{- 9}

C are placed 6 m apart. Find the electric field intensity ratio at point 4 m from the centre of the electric dipole

(i) on axial line

(ii) on equatorial line

+ 3.2 \times 10^{- 19}

- 3.2 \times 10^{- 19}

2.4 ˙ A

apart form an electric dipole. It is placed in a uniform electric field of intensity

4 \times 10^{5}

volt/m. The electric dipole moment is

Q. Two opposite charges each of magnitude

2 μ C

1 c m

apart. Find a electric field at a distance of

5 c m

from the mid-point on axial line of the dipole. Also find the field on equatorial line at the same distance from mid-point.

Join BYJU'S Learning Program

similar_icon

Related Videos

lock

Electric Field inside a Conductor

PHYSICS

Watch in App

explore_more_icon

Explore more

Electric Field inside a Conductor under Electrodynamic Conditions

Standard XII Physics

Join BYJU'S Learning Program

CrossIcon