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Byju's Answer
Standard XII
Physics
Equations of Motion
44.A ball thr...
Question
44.A ball thrown with a velocity of 49m/s got the maximum range measured in the atmosphere as 225m.The decrease in range due to atmosphere is
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Solution
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e
m
a
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r
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R
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g
=
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×
49
9
.
8
=
245
m
.
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Similar questions
Q.
A ball thrown with a velocity of
49
m
s
−
1
got the maximum range recorded in the atmosphere as
225
m
. The decrease in range due to the atmosphere is
Q.
The maximum horizontal range of a ball projected with a velocity of
40
m
/
s
is (take
g
=
9.8
m
/
s
2
)
Q.
A boy throws a ball with a velocity of
20
m
s
−
1
such that it's horizontal range is maximum. If
g
=
10
m
/
s
2
, range of the ball is
Q.
[
a
]
Its velocity at the highest point is
18
√
2
m/s.
[
b
]
Its velocity at the highest point is zero.
[
c
]
If it is thrown at a larger angle to the horizontal, then both its range and maximum height will decrease.
[
d
]
Range will decrease while maximum height will
increase if angle of projection is increased.
A projectile thrown at an angle of
45
to the horizontal has a range of
32.4
m
. Given:
g
=
10
m
s
−
2
. Which of the following is correct?
Q.
A body is thrown with velocity of 40 m/s in a direction making an angle of
30
0
with the horizontal.
Calculate i) Horizontal range, ii) Maximum height and iii) Time taken to reach the maximum height.
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