Question

A body is thrown with velocity of 40 m/s in a direction making an angle of ${30}^0$ with the horizontal.
Calculate i) Horizontal range, ii) Maximum height and iii) Time taken to reach the maximum height.

• A. (a)$131.4m$(b)$20.41m$(c)$2.041s$
• B. (a)$121.4m$(b)$24.41m$(c)$2.091s$
• C. (a)$141.4m$(b)$20.41m$(c)$2.041s$
• D. (a)$161.4m$(b)$10.41m$(c)$2.051s$

Answer 1

The correct option is C (a)$141.4m$

(b)$20.41m$

(c)$2.041s$

R.E.F image

$u=40m/s$

$\theta ={30}^{\circ }$

$g=9.81$

Time of flight, $T=\frac{2usin\theta }{g}$

Maximum Height, $H=\frac{u^{2}si{n}^2\theta }{2g}$

Horizontal Range, $R=\frac{u^{2}sin2\theta }{g}$

Time taken to reach the

max.height, t $=\frac{T}{2}$

$4=\frac{\left(40{)}^2\right(sin{30}^{\circ }{)}^2}{2\times 9.8}=20.408m$

$=20.41m$

$R=\frac{(40{)}^{2}sin2\times {30}^{\circ }}{9.8}=141.4m$

$t=\frac{I}{2}=\frac{usin3\theta }{g}=2.041s$

Ans $=141.4m,20.41m,2.041s$ (C)