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Question

45 g of ethylene glycol is mixed with 600 g of water. What is the freezing point of the solution? kf=1.86 K kg mol−1.

A
270.90 K
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B
270.90
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C
273 K
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D
274.15 K
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Solution

The correct option is C 270.90
45 g of ethylene glycol is mixed with 600 g of water.
Molar mass of ethylene glycol =62 g/mol
45 g ethylene glycol =4562=0.726 moles.
600 g water =0.600 kg
Molality (m)=0.726mol0.600kg=1.21m
The depression in the freezing point ΔTf=Kfm=1.86×1.21=2.25K
The freezing point of pure water =273.15 K.
Freezing point of solution =273.15+2.25=270.90 K
Hence, the option (B) is the correct answer.

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