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Byju's Answer
Standard XII
Chemistry
Depression in Freezing Point
45 g of ethyl...
Question
45
g
of ethylene glycol is mixed with
600
g
of water. What is the freezing point of the solution?
k
f
=
1.86
K
k
g
m
o
l
−
1
.
A
−
270.90
K
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B
270.90
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C
273
K
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D
274.15
K
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Solution
The correct option is
C
270.90
45 g of ethylene glycol is mixed with 600 g of water.
Molar mass of ethylene glycol
=
62
g/mol
45 g ethylene glycol
=
45
62
=
0.726
moles.
600 g water
=
0.600
kg
Molality
(
m
)
=
0.726
m
o
l
0.600
k
g
=
1.21
m
The depression in the freezing point
Δ
T
f
=
K
f
m
=
1.86
×
1.21
=
2.25
K
The freezing point of pure water
=
273.15
K.
Freezing point of solution
=
273.15
+
2.25
=
270.90
K
Hence, the option (B) is the correct answer.
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