450 ml of oxygen gas is collected at 27°C. If for a particular use, the volume has to be reduced to 13 of its original volume, find the temperature to which the gas has to be cooled ? [pressure constant]
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Solution
Let V1betheoriginalvolumeoftheoxygengas=450mlT1betheinitialtemperatureoftheoxygengasinK=273+27=300KV2bethefinalvolumeoftheoxygengas=13×V1=13×450=150mlT2bethefinaltemperatureofthegasinK=?
By Charles law
V1T1=V2T2Substitutingthevalues:450300=150T2∴T2=150x300450∴T2=100K=[100−273]°C=–173°C
Therefore the temperature to which the gas has to be cooled is - 173°C.