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Question

450 ml of oxygen gas is collected at 27°C. If for a particular use, the volume has to be reduced to 13 of its original volume, find the temperature to which the gas has to be cooled ? [pressure constant]

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Solution

Let
V1 be the original volume of the oxygen gas = 450 ml T1 be the initial temperature of the oxygen gas in K = 273 + 27 = 300 K V2 be the final volume of the oxygen gas = 13 × V1 = 13 ×450 = 150 ml T2 be the final temperature of the gas in K = ?

By Charles law

V1T1 =V2T2 Substituting the values : 450300=150T2 T2= 150x300 450T2 = 100 K = [ 100273]°C = 173°C
Therefore the temperature to which the gas has to be cooled is - 173°C.

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