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Relation between Linear and Angular Speed

47.Orbital ve...

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47.Orbital velocity of a satelite at a height 3400km from the earth?? g=9.8

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Q. A remote-sensing satellite of earth revolves in a circular orbit at a height of

0.25 \times 10^{6}

m

above the surface of earth. If earth's radius is

6.4 \times 10^{6} m

g = 9.8 m s^{- 2}

, then the orbital speed of the satellite is

Q. Write the equation for orbital velocity of a satellite orbiting the earth at a height of

h

from the surface of the earth.

Q. An artificial satellite is moving in a circular orbit around the earth with a speed equal to half of the magnitude of escape velocity from the earth. If the satellite is stopped suddenly in its orbit and allowed to fall freely onto the earth, find the speed

(km/sec)

with which it hits the surface of the earth.

(g = 9.8 {ms}^{- 2}

and Radius of earth

= 6400 km)

Q. A remote-sensing satellite of earth revolves in a circular orbit at a height of

0.25 \times 10^{6}

m

above the surface of earth. If earth's radius is

6.4 \times 10^{6} m

g = 9.8 m s^{- 2}

, then the orbital speed of the satellite is

The orbital velocity of satellite at a height R above the surface of Earth is v . The escape velocity from that location is

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Relation between Linear and Angular Speed

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