Question

$(48x-8)+6=29$

Given the above equation, what is the value of 6x$-1$?

• A. $\frac{23}{8}$
• B. $\frac{11}{4}$
• C. $\frac{5}{4}$
• D. $\frac{28}{8}$

Answer 1

The correct option is A $\frac{23}{8}$

Notice that $(48x-8)$ is 8 times $(6x-1)$.

Subtract 6 from both sides

$(48x-8)+6-6=29-6$

Factor 8 from the expression $(48x-8)$

$8(6x-1)=23$

Dividing 8 from both sides

$8(6x-1)÷8=23÷8$

$(6x-1)=\frac{23}{8}$

Thus, the value of 6x$-1$ is $\frac{23}{8}$.