4a^2+4ab+b^2 =(2a)^2+4ab+b^2 using identity: (a+b)^2=a^2+2ab+b^2 ⇒ 4a^2+4ab+b^2=(2a+b)^2 ...

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Factorisation Using Algebraic Identities

4a2+4ab+b2=

Question

$4 a^{2} + 4 a b + b^{2} =$

(a + 2 b)^{2}

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(2 a + b)^{2}

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(2 a - b)^{2}

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(a - 2 b)^{2}

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Solution

The correct option is B $(2 a + b)^{2}$
$4 a^{2} + 4 a b + b^{2}$
$= (2 a)^{2} + 4 a b + b^{2}$
using identity: $(a + b)^{2} = a^{2} + 2 a b + b^{2}$
$\Rightarrow 4 a^{2} + 4 a b + b^{2} = (2 a + b)^{2}$

Suggest Corrections

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(2 a + b)^{2} = 4 a^{2} + b^{2} + 4 a b

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