Question

$$\begin{gathered} 4x-3y=8, \\ 6x-y=\frac{29}{3}. \end{gathered}$$

Answer 1

The given system of equation is:
4x − 3y = 8 .........(i)
$6x-y=\frac{29}{3}$ ........(ii)
On multiplying (ii) by 3, we get:
18x − 3y = 29.........(iii)

On subtracting (iii) from (i) we get:
−14x = −21
⇒ x = $\frac{21}{14}=\frac{3}{2}$
On substituting the value of x = $\frac{3}{2}$ in (i), we get:
$$\begin{gathered} 4\times \frac{3}{2}-3y=8 \\ \Rightarrow 6-3y=8 \\ \Rightarrow 3y=6-8=-2 \\ \Rightarrow y=\frac{-2}{3} \end{gathered}$$
Hence, the solution is x = $\frac{3}{2}$ and y = $\frac{-2}{3}$.