Factorize-12x-y2-x-y-35A- 4 x-4 y-73 x-3 y-5B- 4 x -73 y -5- 4 x-4 y-73 x-3 y-5D- 3 x-3 y-74 x-4 y-5

The correct option is C (4x + 4y 7)(3x + 3y + 5) ⇒ 12(x+y)^2 (x+y) 35 Taking (x+y) = k ⇒ 12k^2 k 35 ⇒ 12k^2 + 20k 21k 35 ∵ (20).( 21) = (12).( 35 ...

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Byju's Answer

Standard VIII

Mathematics

Factorisation Using Algebraic Identities

Factorize:12x...

Question

Factorize:

$12 (x + y)^{2} - (x + y) - 35$

$(4 x - 7) (3 y + 5)$

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$(4 x + 4 y - 7) (3 x + 3 y + 5)$

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$(3 x + 3 y - 7) (4 x + 4 y + 5)$

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$(4 x + 4 y + 7) (3 x + 3 y - 5)$

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Solution

The correct option is B
$(4 x + 4 y - 7) (3 x + 3 y + 5)$

$\Rightarrow 12 (x + y)^{2} - (x + y) - 35$

Taking $(x + y) = k$

$\Rightarrow 12 k^{2} - k - 35$

$\Rightarrow 12 k^{2} + 20 k - 21 k - 35$ $∵ (20) . (- 21) = (12) . (- 35) a n d (- 21 + 20 = - 1)$

$\Rightarrow 4 k (3 k + 5) - 7 (3 k + 5)$

$\Rightarrow (4 k - 7) (3 k + 5)$

$\Rightarrow (4 (x + y) - 7) (3 (x + y) + 5)$

$\Rightarrow (4 x + 4 y - 7) (3 x + 3 y + 5)$

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Similar questions

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which are parallel to the straight line 4x + 3y + 5 = 0, are

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Factors of $18 y^{2} + 24 x y + 36 y$ are:

\frac{4}{x} + 3 y = 8, \frac{6}{x} - 4 y = - 5 .

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Factorize: 12(x+y)2−(x+y)−35

The correct option is B (4x+4y−7)(3x+3y+5) ⇒12(x+y)2−(x+y)−35 Taking (x+y)=k ⇒12k2−k−35 ⇒12k2+20k−21k−35 ∵(20).(−21)=(12).(−35) and (−21+20=−1) ⇒4k(3k+5)−7(3k+5) ⇒(4k−7)(3k+5) ⇒(4(x+y)−7)(3(x+y)+5) ⇒(4x+4y−7)(3x+3y+5)

Factorize:

$12 (x + y)^{2} - (x + y) - 35$