Question

$4yz(z^2+6z-16)÷2y(z+8)$ gives

• A. z-2
• B. z(z-2)
• C. 2z(z-2)
• D. None of these

Answer 1

The correct option is C

2z(z-2)

$4yz(z^2+6z-16)=4yz[z^2-2z+8z-16]=4yz\left[z\right(z-2)+8(z-2\left)\right]=4yz(z-2)(z+8)\text{Therefore,}\left(4yz\right(z^2+6z-16\left)\right)÷\left(2y\right(z+8\left)\right)$

$=\frac{4yz(z-2)(z+8)}{2y(z+8)}=2z(z-2)$