5^{2x+1}÷25=125

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5^{2 x + 1} \div 25 = 125

x

x

5^{2 x + 1} \div 25 = 125

5^{2 x + 1} / 25 = 125,

x

If $5^{2 x + 1} \div 25 = 125$ , find the value of $x$ .

x : 125 = 5^{2 x - 1}

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