Condition (1)
First two digit
5×3=15
9×2=18
8×6=48
5×4=20
Condition (2)
First and last digit
5×2=10
9×4=36
8×3=24
5×5=25
Condition (3)
(IInddigit+IIIrddigit)×(Istdigit)−(IInddigit)=solution
(3+2)×5−3=22
(2+4)×9−2=52
(6+3)×8−6=66
(4+5)×5−4=41
Then, condition (1) (2) and (3) to,
5+3+2=151022
9+2+4=183652
8+6+3=482466
5+4+5=202541
Then,
7+2+5=143547
Hence, this is the answer.