Question

$5$ boys have in total $n+3$ chocolates. If one more boy joins the group, there are in total $2n$ chocolates. Find the number of chocolates the sixth boy has.

• A. $7n-15$
• B. $5n$
• C. $n+18$
• D. $n+10$

Answer 1

The correct option is A $7n-15$

Given that boys have total $n+3$ chocolates.

If one more boy joins the group the total average is $2n$.

Then five boys have total chocolate $=5(n+3)$

And six boys have total chocolates $=7\left(2n\right)=14n$

Then sixth boy have chocolates $=14n-(5n+15)=14n-5n-15=7n-15$