Question

(5) Draw ∆IRD, such that l (RD) = 3.8 cm, l (ID) = 4.2 cm and m$\angle R$ = 90°.

Answer 1

Steps of construction :

(1) Draw a line segment RD = 3.8 cm.
(2) Placing the protractor at vertex R on segment RD, draw $\angle XRD=$ 90°.
(3) Taking D as centre, draw an arc of radius 4.2 cm that intersects the ray XR at I.
(4) Join I and D.
The required ∆IRD is thus drawn.