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Question

# Draw triangles according to the measures given below. (1) In ∆ABC, m∠A = 90°, l (AB) = 3.8 cm, l (BC) = 4.2 cm. (2) In ∆DEF, m∠E = 90°, l (EF) = 4 cm, l (DF) = 4.5 cm. (3) In ∆PQR, m∠Q, 90°, l (QR) = 4 cm, l (PR) = 6 cm.

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Solution

## (1) Steps of construction of the given triangle are as follows: (i) Draw a line segment AB = 3.8 cm. (ii) Placing the protractor at vertex A on segment AB, draw ∠XAB = 90°. (iii) Taking B as centre draw an arc of radius 4.2 cm that intersects the ray AX at C. (iv) Join B and C. Hence, we get the required ∆ABC. (2) Steps of construction of the given triangle are as follows: (i) Draw a line segment EF = 4 cm. (ii) Placing the protractor at vertex E on segment EF, draw ∠XEF = 90°. (iii) Taking F as centre draw an arc of radius 4.5 cm that intersects the ray EX at D. (iv) Join D and F. Hence, we get the required ∆DEF. (3) Steps of construction of the given triangle are as follows: (i) Draw a line segment QR = 4 cm. (ii) Placing the protractor at vertex Q on segment QR, draw ∠XQR = 90° (iii) Taking R as centre draw an arc of radius 6 cm that intersects the ray QX at P. (iv) Join P and R. Hence, we get the required ∆PQR.

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