CameraIcon

SearchIcon

MyQuestionIcon

1

You visited us 1 times! Enjoying our articles? Unlock Full Access!

Locus of the Points Equidistant From Two Intersecting Lines

Construct tri...

Question

Construct triangles of the measures given below.
In ∆PQR, l(PQ) = 4.5 cm, l(PR) = 11.7 cm, m ∠PQR = 90^°.

Open in App

Solution

Steps of construction
1. Draw a line PQ = 4.5 cm.
2. With Q as centre, draw ∠XQP = 90º.
3. With P as centre and 11.7 cm as radius, cut an arc on XQ and name it as point R.
4. Join RP.
∆PQR is thus formed.

Suggest Corrections

thumbs-up

7

Similar questions

Draw triangles with the measures given

∆

ABC , l(AB) = 5.5 cm,l(BC) = 4.2 cm, l(AC) = 3.5 cm

(b) In ∆ STU, l(ST) = 7 cm, l(TU) = 4 cm, l(SU) = 5 cm

(c) In ∆ PQR, l(PQ) = 6 cm, l(QR) = 3.8 cm, l(PR) = 4.5 cm

Q. In parallelogram PQRS, l(PQ) = 3.5 cm, l(QR) = 4.5 cm, l(PR) = 6.5 cm.

Q. Construct triangles of the measures given below.

In ∆ABC, l(AC) = 7.5 cm, m ∠ABC = 90^° , l(BC) = 5.5 cm.

Q. Construct triangles of the measures given below.

In ∆MAN, m ∠MAN = 90^°, l(AN) = 8 cm, l(MN) = 10 cm.

Q. Draw triangles according to the measures given below.

(1) In ∆ABC, m∠A = 90°, l (AB) = 3.8 cm, l (BC) = 4.2 cm.
(2) In ∆DEF, m∠E = 90°, l (EF) = 4 cm, l (DF) = 4.5 cm.
(3) In ∆PQR, m∠Q, 90°, l (QR) = 4 cm, l (PR) = 6 cm.

View More

Join BYJU'S Learning Program

similar_icon

Related Videos

lock

Locus of the Points Equidistant from Two Intersecting Lines

MATHEMATICS

Watch in App

explore_more_icon

Explore more

Locus of the Points Equidistant From Two Intersecting Lines

Standard X Mathematics

Join BYJU'S Learning Program

CrossIcon