5 g of Zinc is treated separately with an excess of
I. dilute hydrochloric acid and
II. aqueous sodium hydroxide.
The ratio of the volumes of H2 evolved in these two reactions is:
A
1:2
No worries! We‘ve got your back. Try BYJU‘S free classes today!
B
1:1
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
C
1:4
No worries! We‘ve got your back. Try BYJU‘S free classes today!
D
2:1
No worries! We‘ve got your back. Try BYJU‘S free classes today!
Open in App
Solution
The correct option is B1:1 Zn+2NaOH→Na2ZnO2+H2 Zn+2HCl→ZnCl2+H2
So, the ratio of volume of H2 released in both the cases is 1:1.