5 gram of ethane are confined in a bulb of one liter capacity. The bulb is so weak that it will burst if the pressure reaches 10 atm. At what temperature the bulb burst ?

730.8 K

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73.08 K

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1461.6 K

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273.15 K

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Solution

The correct option is A $730.8 K$
Temperature at which the pressure reaches 10 atm can be calculated using idal gas equation.
From Ideal gas equation, we know

$P V = n R T \Rightarrow T = \frac{P V}{n R} = \frac{10 a t m \times 1 L}{\frac{5}{30} \times 0.0821 L . a t m} (n = \frac{W e i g h t}{M o l e c u l a r M a s s}) = 730.8 K$

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