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Question

5 grams caco3 on heating produced 112 CC of CO2 at STP what is the extent of reaction?

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Solution

CaCO3 CaO+CO2100 g 22.4 L or 22400 ml100 g of CaCO3 gives 22400 ml of CO25 g of CaCO3 gives = 22400100 × 5 = 1120 mlThe given amount of CO2 is 112 ml only. That means still more amount of productshould be formed. So the reaction occurs very slowly

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