Question

$5$ letters $A,B,E,L,T$ are written on $5$ tickets and then the tickets are arranged at random. The probability that the letters on the tickets arranged at random is the word $TABLE$ is

• A. $1$
• B. $\frac{1}{60}$
• C. $\frac{1}{120}$
• D. $\frac{1}{30}$

Answer 1

Answer: (C)

$\frac{1}{120}$

Total words $=5!=120$
$\Rightarrow P=1/120$