Question

5-litre vessel contains $2$ moles of each of gases $A$ and $B$ at equilibrium. If $1$ mole each of $A$ and $B$ are removed.

Calculate $K_c$ for the reaction $A\left(g\right)\rightleftharpoons B\left(g\right)$.

Answer 1

The given reaction is:

$A\left(g\right)\rightleftharpoons B\left(g\right)$

$K_C=\frac{\left[B\right]}{\left[A\right]}=\frac{2/5}{2/5}=1$

At equilibrium, 2 moles of each gas were present in 5L vessels. Now, 1 mole of each is removed. Now, moles left of A & B = 1 mole.

So, $K_C=\frac{\left[B\right]}{\left[A\right]}=\frac{1/5}{1/5}=1$

The correct answer is 1