Question

5 men and 4 women are to be seated in a row so that the women occupy the even places. How many such arrangements are possible?

• A. 2880
• B. 1440
• C. 720
• D. 2020

Answer 1

The correct option is A 2880

There are total 9 places out of which 4 are even and rest 5 places are odd.
4 women can be arranged at 4 even places in 4! ways.
and 5 men can be placed in remaining 5 places in ${}^5{P}_5$ ways,
Hence, the required number of permutations.
$=4!{\times }^5{P}_5=24\times 120=2880$