$5$ ml of $1 N$ HCl, $20$ ml of $\frac{N}{2}$ $H_{2} S O_{4}$ and $30$ ml of $\frac{N}{3}$ $H N O_{3}$ are mixed together and the volume is made to $1$ L. The normality of the resulting solution is :

\frac{N}{5}

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\frac{N}{10}

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\frac{N}{20}

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\frac{N}{40}

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Solution

The correct option is D $\frac{N}{40}$
$N_{1} V_{1} + N_{2} V_{2} + N_{3} V_{3} = N_{4} V_{4}$

$V_{4} =$ Final volume $= 1 L$

$5 \times N + 20 \times \frac{N}{2} + 30 \times \frac{N}{3} = N_{4} \times 1000$

$∴ N_{4} = \frac{N}{40}$

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Similar questions

5 ml of N HCl, 20 ml of $N / 2 H_{2} S O_{4}$ and 30 ml of $N / 3 H N O_{3}$ are mixed together and volume made to one litre. The normality of the resulting solution is

5 m L

N H C l, 20 m L

N / 2 H_{2} S O_{4}

and

30 m L

N / 3 H N O_{3}

are mixed together and volume made to

1 L

The normality of the resulting solution is :

5 ml of N HCl, 20 ml of $N / 2 H_{2} S O_{4}$ and 30 ml of $N / 3 H N O_{3}$ are mixed together and volume made to one litre. The normality of the resulting solution is

10

ml of

N H_{4} C l

20

ml of

N / 2 H_{2} S O_{4}

and

30

ml of

N / 3 H N O_{3}

are mixed together and volume made to one litre. Normality of resulting solution is:

Q. Normality of solution obtained by mixing 10 mL of 1 N

H C I

, 20 mL of 2 N

H_{2} S O_{4}

and mL of 3 N

H N O_{3}

is:

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5 ml of 1N HCl, 20 ml of N2 H2SO4 and 30 ml of N3 HNO3 are mixed together and the volume is made to 1 L. The normality of the resulting solution is :

The correct option is D N40N1V1+N2V2+N3V3=N4V4V4= Final volume =1 L5×N+20×N2+30×N3=N4×1000∴N4=N40

$5$ ml of $1 N$ HCl, $20$ ml of $\frac{N}{2}$ $H_{2} S O_{4}$ and $30$ ml of $\frac{N}{3}$ $H N O_{3}$ are mixed together and the volume is made to $1$ L. The normality of the resulting solution is :

The correct option is D $\frac{N}{40}$
$N_{1} V_{1} + N_{2} V_{2} + N_{3} V_{3} = N_{4} V_{4}$

$V_{4} =$ Final volume $= 1 L$

$5 \times N + 20 \times \frac{N}{2} + 30 \times \frac{N}{3} = N_{4} \times 1000$

$∴ N_{4} = \frac{N}{40}$