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Question

50.0mL of 0.10MHCl is mixed with 50.0mL of 0.10M,NaOH. The solution temperature rises by 3.0C.

Calculate the enthalpy of neutralization per mole of HCl?

A
2.5×102kJ
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B
1.3×102kJ
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C
8.4×101kJ
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D
6.3×101kJ
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Solution

The correct option is C 2.5×102kJ
HCl+NaOHNaCl+H2O
enthalpy change =mCvdT=100×4.2×3
=1.26kJ
enthalpy change for 5 millimole =1.26kJ
enthalpy change for 1 mole 1.265×103
2.52×102kJ

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